更新时间:2024-03-06 18:12:33
大家好,我是小环,我来为大家解答以上问题。二次根式的乘除法,二次根式的乘除很多人还不知道,现在让我们一起来看看吧!
1、1.(根号2x-3倍根号8x^3)÷根号(x/4) =((2x)^0.5-3*(8x^3)^0.5/(x/4)^0.5 =((2x)^0.5-6x*(2x)^0.5)/(x^0.5/2) =(2*(2x)^0.5-12x*(2x)^0.5)/(x^0.5) =2*(2^0.5)-12*(2^0.5) =-10*(2^0.5) 2.2倍根号12×根号3/4÷5倍根号2 =2*(12^0.5)*(3^0.5/4)/(5*(2^0.5)) =4*(3^0.5)*(3^0.5/4)/(5*(2^0.5)) =3/(5*(2^0.5)) =3*(2^0.5)/10 =0.3*(2^0.5) 3.(4倍根号2-3倍根号6)÷2倍根号2 =(4*(2^0.5)-3*(6^0.5))/(2*(2^0.5)) =(4-3*(3^0.5))/2 =2-3*(3^0.5))/2 4.(根号48+1/4根号6)÷根号27 =(48^0.5+(6^0.5)/4)÷(27^0.5) =(4*3^0.5+(6^0.5)/4)/(3*3^0.5) =(4+(2^0.5)/4)/3 =4/3+(2^0.5)/12。
本文到此讲解完毕了,希望对大家有帮助。